Bengaluru: After being restricted to just 46 runs in the first innings of the Bengaluru Test match, Team India made a bright start in the second innings. When Team India captain Rohit Sharma and Yashasvi Jaiswal came on the field, they looked in a different style. Both the batsmen made it clear from the very first over that they were not going to stop and play. Especially Rohit Sharma was batting in T20 mode. During this, he bowled Matt Henry in the 21st over. Rohit Sharma completely stunned the Kiwi bowler by hitting three back to back boundaries in Matt Henry’s over. Rohit Sharma faced the first ball of the 21st over. Rohit took a single on the first ball and gave the strike to Virat Kohli. After this, Virat Kohli was also able to score only one run on the second ball. In such a situation, Rohit Sharma returned to strike again.
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Rohit Sharma scored 14 runs in three balls
After going on strike for the second time, Rohit Sharma changed his gear and hit the fourth ball. The ball fell very close to the boundary, but the rope remained inside. In such a situation, the umpire declared it a four. However, in the fourth over, Rohit Sharma took the ball out of his trap and sent the ball towards the mid-wicket stand. Even on the fifth ball, Rohit Sharma was trying to hit a big shot, but only a four was hit on that ball. However, a single run was scored on the last ball.
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In this way, Team India got a total of 16 runs in this over of Matt Henry, out of which Rohit Sharma scored 15 runs. However, in the very next over, Rohit Sharma was unlucky and was bowled. In this way Rohit Sharma was out after scoring 52 runs in 63 balls.