Bumrah five wickets restricted South Africa for 210- Dinamani

by time news

File photo

South Africa were bowled out for 210 in the first innings of the 3rd Test against India.

The 3rd and final Test match of the series between South Africa and India is being played in Cape Town. India won the toss and elected to bat first, losing by 223 runs. South Africa, who started the first innings consecutively, were 176 for seven at tea on the second day. Keegan Peterson was unbeaten on fifty.

Read this too | South Africa lost by 7 wickets: Petersen showing restraint

After the break, the Indian bowlers began to dominate. Jaspreet Bumra dismissed Petersen for 72 not out.

After this, Kakiso Rabada tried to get close to India’s first innings run. Rabada, who lifted the team’s score to 200, was bowled out for 15 by Shardul Thakur. Bumrawe also dropped Lungi Ngiti for the last wicket.

South Africa were bowled out for 210 in 76.3 overs. With this, the Indian team has a lead of 13 runs.

For India, Bumra top-scored with 5, followed by Umesh Yadav and Mohammad Shami (2) and Shardul Thakur (1).

.

You may also like

Leave a Comment