HYDERABAD: India and Australia face off tonight in the third T20I to decide who will win the series as both teams have won a match apiece.
Australia won the first match at Mohali. In this case, the 2nd match was held in Nagpur last night.
Australia batted first in the match which was shortened to eight overs due to rain. The team added 90 runs for the loss of five wickets in eight overs. Indian spinner Axar Patel bowled two overs, conceding only 13 runs and taking two wickets.
In the Indian team that bowled next, captain Rohit Sharma scored 46 runs off 20 balls and stayed on till the end. Dinesh Karthik, who came last, hit a boundary and a six off two balls. After this, the Indian team won by six wickets with four balls to spare.
Rohit tops the six
Rohit Sharma tops the list of most sixes in T20 Internationals. He has hit 176 sixes so far, including the four sixes he hit in the previous day’s match. Martin Cupdle (172, New Zealand), Chris Gayle (124, West Indies), Morgan (120, England) and Aaron Finch (119, Australia) are next.