At the same time, Team India, who have won the first match and lead the series 1-0, are aiming for nothing less than winning the next match to clinch the three-match series. That would make them the strongest possible playing eleven for this match as well. With hours to go before the second match, let’s see what Team India’s likely playing XI will look like.
Top order
It was the team’s top-order batsmen who performed best for India in the first match. The performance of openers Shikhar Dhawan and Shubman Gill was remarkable in this. While Dhawan scored 97 runs, Gill scored 64 runs. Shreyas Iyer, who batted at number three, shone with 54 runs. These three will play in the team’s top order in the second ODI as well. If they can shine even today, things will be easy for India.
middle row
The in-form Suryakumar Yadav will bat at number four. Surya will try to make up for the fatigue of not being able to shine in the first match with a good innings. Malayalam star Sanju Samson will be at number five. In the first ODI, he was disappointed with the batting, but the player had a great performance behind the wicket. With that, the team management may be ready to give the player another chance. Sanju will be followed by Deepak Hooda and Axar Patel.
Ballers
Mohammad Sirajina, who led India’s pace line in the first ODI, will continue that task today. He is rumored to have Shardul Thakur as his partner. But Prasid Krishna, who was in the team in the last game, may have to leave the team at times. If Prashid is replaced, one of Arshdeep Singh and Josh Khan may make the team. At the same time, Yuzvendra Chahal will continue to play as a specialist spinner.
India’s Prospective XI is as follows – Shikhar Dhawan, Shubman Gill, Shreyas Iyer, Suryakumar Yadav, Sanju Samson, Deepak Hooda, Axar Patel, Shardul Thakur, Mohammad Siraj, Yuzvendra Chahal, Prasid Krishna/Arshdeep Singh/Avesh Khan.
Flying Sanju, Sanju won India